# User:108x16

1ʘȣ×16

 This user is an Australian... Strewth! Crikey! Fark!(List of Australian Uncyclopedians)

i trailled Wesley Snipes for 3 years to write an article on him... that is all

# editCurrent Research

Help is appreciated with my current theorems

## editBob Marley Maths Theorems

### editThe root of evil theorem

“Every..Every..Everywhere you go, Woman is the root of all evil”
~ Bob Marley on Maths and Women: song-Adam and Eve

alternatively can be represented as $woman = \sqrt[x]{lim_{-\infty\rightarrow \infty} (evil)}$

this is also supported by the song 'No Woman, No Cry which postulates that a condition for Cry is Woman.

unfortunately I can only assume x=2 and that this is a square route, clues to the value of x may lie in this song, or others... i will keep searching

### editThe 2 joint maximum theorem

“I smoke two joints in the morning I smoke two joints at night, I smoke two joints in the afternoon and it makes me feel alright smoke two joints in time of peace and two the time of war smoke two joints before i smoke two joints

and then i smoke some more”
~ Bob Marley on Maths and Joints

'Assumptions

"some more" is a non negative integer constant represented by (S)

Marley's Colleague Peter Tosh said

“I don't want no peace

I need equal rights and justice”
~ Peter Tosh on Peace

so time of peace = 0% therefore time of war = 100%

Morning =12am

Afternoon=12pm

Night = 6pm

Complications arise with the following phrase which will be dealt with. smoke two joints before i smoke two joints

Simplest Case

Assuming 2 joints must only be smoked before the other two joint times (except morning which would fall on the previous day) the minimum amount of joints that may be smoked is

$(2_{morning}j) + (2_{afternoon}j + 2_{before}j) + (2_{night}j + 2_{before}j) + (2_{war}j + 2_{before}j) +S = 14j + Sj = j(14 + S)$ when $S=0 , j_{min}=14j$

so the minimum case is 14 joints in a day

Maximum Case

assume the time to smoke a joint is $t_j$

joints need not be smoked in sets of two as "Some More" can be any non negative integer.

therefore the number of joints able to be smoked in a day is:

$j_{max}=60*60*24/t$ as t tends toward 0, j_{max} approaches infinity

$j_{max} \rightarrow \infty ; t\rightarrow 0$

this would also be the case if you smoke more than 1 joint at a time.

Range and Conclusions'

j ranges from 14 to infinity!

bob marley smoked at least 14 joints a day - 18 in the special case of war turning to peace or vice versa. ( 2 in the alternate scenario + 2 before)

Bob was alive for 13243 days and a few hours (forget about those)

therefore, assuming there was spotaneous occurences of peace in the world, Bob smoked at minimum of 185,402 joints which is a hell of a lot. Then again 3 of his children were born to 3 different mothers within a month of each other. The guy is a super-hero.

==

Help would be appreciated on how stoned you would get.

i am assuming you could just plug in some constants, but thats no fun.. i want evidence.